The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_s_rY0Nib7rPDmf7XEREQqCKdgFdcu5-cQOV4QpuofknXNQCvSEXEgaMeg6CUoiUIgkQ_dIxFE-mBK2KAVxIx9Xumf0Ctbb8NMvS17Q8726ANke11WbKx3jdknVS-Ufy__gvcMNZY-3Benl5LiWJV18ghaTuIv9VuCqdaIERDsIO9RJd8KSXi1xonkK6u5IZEjx33_h86eSKUqHiBctC_4ZeA66K_0i0m2a7GSYXnNVw4GOvsx6k3tvpi4z5wGXZASUJTXNpwCrU7DLQEtBFM6gNo4bSsWcrB60TtxziCR20j7H5QsUTBnXagF8JrjIwzROEQUH2sigkiYwkSIh_MzCM4FikV2F_PVwlV6lO4zDNhVLNP5tAY0COC2nvDMSrO95k1Ji1sDVA2TVjV7f5QxAsTG5yIklW5SR8WBh3I9u9AEMRUa04NkqsKlG_8T1w8nugesNCyHWR5nmbnCU_56N17VRH1Q_NczVUC4EixcqWGCajY4wnNjWsBBaNG4AS70bPZ-LrJll6P0L07Mbg7W4Rpb1ujHF0lhzIKunQIrOW3vePn6n133HhOjzknywNM4F8HHkSLPqVYEWrmKb9ueZA0JpwgJ8buM5w9gUooPK4l0HAaQzDS0obJR8Ko7VhTMOBX7OeFtiCM30cQOF3gmr_ze62FmQC4f1rzBR_f_RlNT8HXCCDqpAQkIo2Zm8ZvLTRb-AfO14zASkBN4EvdPa8EX-v4VhmdAbeWpOYcsT6jpc3NU6sD_VDe7RTG-ktDaPr3LAd9RSF2iaUBgiDyYvqaIg640_iKz52ZEZds9DtCu7cVGhmgkMecnuvqjqTLFTMvLM5MjH_-J4O6wqIP8V0eW1qngkRwGKQzi6SIRAcYAgU-lBJeeiYg=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tiG-wZnCruUArv4CiJu4LUrAO9iVxPeJ2q8UZYmULW7k7OIJwY6shnGj9BHyK5jGcFhqL0te0rvCgAk0OcURJmv1qCE0Mlm62cW59YUDhW2MJxcaSUdSEAsMVQrBu_1mGIZQzf7tMmg4FtUmRhj5JlHrWH00WODKyQOWyJiOHkalIF5t15VrHw9Z3FY8euCw9LEPmgOdn-fFHxDvJO9Gl-oT2Kp5JRvTQy_KJsQB00Io5w86aJo-6MoDgx9S_hBzNgK6AHStyxl_2Rb-i2bYSTxXtqTPUw7XqUqnDwNyUfQvRJU8uirPNv6PCxs9WK8rUWZx2YPUrvwzgZUEbUo1OJMHloFtIdP_WaUoe9S56pom9lC731uVzZD5pxAclT8NqhVwYIt4SOH9WjBgYvsUTykE8BfcKQ5aMQdS20NB1d7f5wHWxr9vCUGthOV4wrU7sdfMZh03uOqdSr1v4VDlSfIJVv17nc0CDotNh5bJnSmX3E12b0VIsFxOUMXlcoxK-KZdVajJrHcJikjNvBP1DoKB55KmDoEp579pDLvF7ShPF6Ah6se_XSY9BpMfJXShKI0e93IzBSIMCsv1au2eZiCpn7XjdimWe59T1QX2_pAy6ZpG27_7raQeBfMYHvcrglMVaWcKSS-kqlVvEpqpUdOHKwMB0g-PQC2i5J3Dmrry41nfZUA-TUB7CnESTFS2cu32cGVKIAzPDpWlLJqV9xaI6gWIGApHGRqAZ6fTP8FsjBRpkmUIL8-9E_CsxXubUdCkEAMrxqqV-XqynwcUR3Qa2MK1vaSUmnXSUy8cpk0vot82rfGKATeyTjrFxwYKOsxO4Q1jRwjOhS44_duIVLb8zRXxATuBhemfTTmEqWjhDTrmXtSrmE1VIEuMRX7ltLv_eqIebSX2vMv0McqzlZ7CzLLNsA5ky38Z6jWqPy13d0zQhfk0j-KSVwFQmlUYk4nddSFtjYK-TVXTWlPR9JDLLjp9rQs6dIt5TIlzK4Y-48u62tmajm6wEMzm8mmg5mqDwQUNJITLoPSi0VNYUV6x85PjLszvtyLcQZbjbpm28Ha2Yzs13gG4SezZa3uptiGsrv0bVe6NY-XgR8RRJpLmjMNcHChifpim4v78sUvaUJ-3LJ6brKUMo35qTN5Gg0N0ceiNi5rznJTFwGm3ZRy9OS286Mj3lm9zZxvjOsRssc2ErhbefhowjBKiyQhV9cCUKDoQYXuy_bXJhKy64NtG7EatZk0BZBBVCaq2vve5b_GSnMe2wH4VkRvQRVgWoJh6osXYXzNJ6g_WX39zSp6jsHA1n1l8NUE-HdqwSUZ6InI5fjX70gqfaTAEA0GK41nlerAdMo41yQJQE0_J3QvgHIdPeIuAplqO95ktE5bmUHdDqllHO9xJodgQ60nhMi0qJy-clmJW-GGxpqpew9UUINvj0dDgtUWY2EAHo_4t-dp04VLwyL729-RANuBWqq4WSCffqoHtGEKHvVSLZN-uB2AIvp0OMpgWr7TbtLwlum_9PDaVZrEwMgpFSwjARji4nCJXZrja9B6i4j9LzqachuNwp-0BaF795-dxUHda8z3W6I04VZCJ3v39IvdDv2qyiSTPo=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sLt3bFQ0us1LQ7jFLJApE70B6qyrKXVt38nl908KZmYVzzGydbsqabH29FHTzAtByrn-Is4rfIjbl_Jc-zAgIT6VgCT883GfA_tv66b_VTljqZjWZJJ49W9cUSGIPXkk_rew26hgDwq99RR_1i1V1Nd5f0V0WlmnlRgr8If9qVsars-Rat_epm_NahA3amoEn-KAmwcSNO0mcgTT_wr-os08GeNwjBqtO__hw6nuYVnABjGfJ4kKxZ1Nn63kZ3wWr-ExSLPluYgVCCGHRYfKXwucbuGh3N-jyHtgwTcKGnnPX64awtN97B3DXsnTfnRnsOC7yVM5X3TABzYfMa-MXYF4ey6wVUkimc97j26cJ_jR2_jt-H6QlGwBQ08xG8bwSI_P8yOhXh6apexUw4mdQmI_51YLFcf1hH0EgslMhnzkB5cU-DN7ceyVkAPH6zCbJ8tRNVVU07ADzIBjhuyofGLPUrULpytY4UX08ks4zCEz0qHRfhbtPdmGr1_XQ4fquWbPVAmpMNUm5uEPYmC3YVsDT-Fjbn9hm6JFqznXyc8vnM=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

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