The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uFN_H5ykCX6qfg6o5cTV9nvFMqIcMEsGBVdRbYavsVAHA3qQYbkeTfl8YFj_WHNLA1KfYjJZ5kr3MIXIUziK8niSF90UTovgcsUTh6VKgsyesBV7PS6Jrt_h5o5owfTiLmjhs306y-pHxAQMXlNyGJiAAp78_dfiowrMDYd2HMEalSXZm0lkfN3lYisdZ-gF2peG3kvKuGzscw2oD-o8WiRCsODB6LfSEwvi1I-0Vj4EIk4kehJtQzcmjSPlod33FclekHsLmIY8rwl3DEZ23DdplFywt1CGtgqpalykDrzoYncNRN2kGhFgnZLsHLv_MJrqP2Xf1pFk7UnT6fvGjO1jXT4yB3tGJHsZNQBP73Mn2auvsjvc0APDxaI40Enzk8VG7kkF2NAw_pFwRyb8XqnC3tALa1WFNKb5PH3bG8r1YXj3hNX_Cq6daduJl1EIPKRj_KB4IqVKSmqQRqCbhCxEveXxyWxrgoBVB_E4VDnelewcde2F4FgK_1zgUD2lGFWukNscmClRbVzRnEZWaFgaeoUzPQVZK8kLjAt7hmND7HLb3T7lGYZGvClXBWkJGTgs-bIXiMdBb3kZjsvnzfseYSA6epJ9f6TZdBU-EVuidouUJhmHI-Egh0vA9OM0kCf_TeVw_NcxwycO1eCZ8q66mEGh-_TiqDhy3dTC3-lm_zY_XS1qPnUHHbMEte8mydUoyLzgwn8INqhc5viCL4Z59n1pS_e9DaBoNHbnifCqO2rp6S0lMQ4v2VuZe50DAyFhweFJKc1OilHI5YAA3_f4OOou0jWSzGtWAz5wCwx8OKPYh2OlLRKtYFUcdzngqIBnpt3C2RNbmb6P3hvVr45Oj4W98ZrLHwjOEnMnvxAIAI97dMPnUC2Q=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vmOl8yBmIK_Kuyy0HXkjEXmc29Bzuss3UxBDSq3I3VO6gcaXI5Sb4DvVrJke_p1lQ-9ZBdvkWPix3JXG3TxYeSg3IVf3o4U1fDINQO1ptui5YSI-5eTVwePoXMSkj4fCfAz0_J8TaX-F5bcjS89bPo5FVnJginzgpsfZYJLLBEROlcpO3hUnKBpikJ3Tfg_S8o1AJEwqjNBTcAiIrJaKhD4OYzYF-LwN3mPfma2c6tPuv3eh-HYuTjpzl1AKjEwqEEELBX8MbpcVyAYsXA9Ssi4fFx-0EYomBYOY_EqqUAQUw7TjO_JRGlUBPzSzfA3e-NDb8zope8SlPoid2Wx4P4pvWZ3Xcl5MmVQ7yBJ8r7KwZVxUM-DwZqdJY_LKVAYlWx6rfM-Oj8D-RF9yfMrWwvWaiXnPcHxrzuudhcHG1MmF-N91Gfyx3aBkc5zLL1QQ50_fsMVaat3329ivj4TCId6w0quZT1tSvZwr_4vyAEL1gdJ5Rq1V4mC84QmH0eWbP9iAW0i92D1dBUJPjNX6boyFC2oQCpO7kvckIpN3zlfGihvgTxjWnMokcmjEwMmWteAak7ZAIpCNnjeuTx0xd6VhoqDIV6BQzUYU240dfzQqNVsa7DqbXRZYrAL40HLb9CynDiaNGyQezemm5Z4UvCnXqT11qa4wIl71ZKFKAFhFKt-D3is8JXqLRCHGCQ-ORBhxq8wXIft8FubO1dcH4Yg2FHCV1xL6Jstx8lvPdxNQDTO9IQWIASRXInqYiQAa87ffqgm33xojZmSwQc8v3VzVBdN4tSycOxm_kivzLgq9xGa9lAT7v_LztsgCkd1flGiJeU8zPPwrecD7yBoedJa-LKS7jUrQQn444M_vcm5vVZQHo3A50_4n2Q63xV9-3n1qEkjABpAUmic1VOVJspVxgSAwppp3FCb3i-7RMQop1q0TJNj1_xAYjRkWpZ8B7WRk6iiH7YZH8RHStwM4gc7dYa74znJUMXSDTUc0hp6vqCRD2_hex9UrLIuBUlGcNcIR0aCpjQa4H_knMC-6egrIB9C4aM5HUxNkzQob3gFsHPTPyeQsI_ZMvoSf4MKYGshi_OW7GUYxbGsWAPUTn2diEp7B8MvoorBDDMGcrNUoJZ4FqiSqVu_nnGLkD81J8bgPlp_teB03NAa0Y6xEZY2dHiBx0TQmjqO0A6mt5ut4hlav_LRJ1b5jLb5uDPO2EyWuUdxad58H4ln8eqWR9U1k9uNqF0EdtTZWgKOngRKkj8W4WZG6bitP18Bx1hHSuuhQCuKrmOAMRXFlhclt2OWxXabpNFfkxm832Bi2E1upWhyl6jgy31vJE8YWD5HxziQkXs_N-R-rfa8qCk3nrUMLtggTsrH8F5N3T1kVXaCiU2sabjdiOkvDs0KXZkEVJzQCZuEpz050FjJliBrhZT5opL_gv-gVG1RZhjdFebzokHC3ZGBqzhlZpzeJcURDVuZxT8PxQeXxDW1zuHUCmWrBeoAGVLZglPjSECQLYsnFQWK1nzMF-LzIXffLrJb3LKWENMsnq3RqRDhUdaFgf4twsXrPobdWmZHBm5LtNMmQ_b9IO5nweoIuDzgoR8_hZXnuUoRaY=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uWLlavGKVnEs3uyaNvJ9CRAK8z443hj7jL8B98tvmgaaHVNYebCrHMg-pw9ZbWxVypDQcKxPJTyqvEHB_1nCscVNTlkNjhiVN6eVJZnhrQ1wmqTIFHnfvuQ1fcPBwpdINU9sZKKZqSMUDROFcCtYL7MZ3o44-Xcxxntn2E9ngGmgdYksaYsj_vqpDRtLHGpIiM6A40rd_0QAcbJlsSF_3wjup81vmimhv1T6PDVme-0xTX2H1Zl4fiaC914YuFx-TFvXsBtloLqYRm200o0HFtCnKHtU1qaZXXi2y46nXg0NMfBCp5xfUpzUB3bjpfYMglh5NnO8JF3X2SypfvddRzufk8SKAKGaRP7nU0Ruo7muw7qWbS2qxFq_ZsEBcPyzBZ7Zb4_T2KIQbuW7HkhT5Ghcs7orcJtVcqXRFnyN4yzrxwu9aH_juur_mDmc4IVIh9X8tATN_hCkVaTL_8TlwVg6jABYA1qwACXwXiL-EunD3SlxOKV_muC-ZlNWZ0DfP5ETcuIFeGl_8Z9YXJ8yIhmZR-hlF0D9agCaRf4RmJsCLc=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

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