The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uIyfY5B6jc5fQbdfchWa4iawlfVrUyQtXUGFe6ENECeVu3CQqgVnfh4sGPlX3C_FIO0vc_3SgXhl9AJW-BSohmGeGzC82k4VzksAbYV72NYg-NSUYMQM71O2QHoylze1ubpMpD81cFeQnc3ciO4jA6Kd_yLMuHYCbCWIPla8VoV3RjLyiNQTq45brb-OrE1Jou0axQonD4-nuxfi5gm9ZTHophNpnXJCABV3SS_UHeStvZjayloqYI2_GqGscuAgBR7hZIG9aZ54pV5Tp1DtlJZBF7uQ-x5MvTZxt4GMe6LHRv7_Kca7AGobgXMEBzGvzBsxMHl_a6xtBMsreqnJqGjNoZaJsbYeChGoeEcdsWYXXuBzB5yocwHMHxIEjF-rTtZtXNreMrrdiFRX8RYIdcjc-edyxlyKs0Eg0ASND1FjTjoLgRW5kLD744zzo18pjFZXp9bs8Szsf6UXk8QFQWl2-OzZnm4YNPxhHk1JLcN2V3fI12ywyVrZ43wNTGAyEdILmw18UukL8KFMf8VaMnml1UBGzCRb1T4AbSQFSfmA7GuWkNZKt0ZxE_GBJ5X8dHhVtTrFTuq2TImcA5te9lDv6UFMCYqbHoXW18QLha7UAEGUHl58NvLt4_TdyV6E71LRb820FyYWZVB1xpqeM4Bp8WYfrNZXZs8OKXvEUxcpPnxY-9F9WgLB1nedzqyE_MkCkLGwc-phdbfQHgHEIWjHGlVESFTFCHDHE2DCLDORDEo-cWjgY_bw4RLx8P4UmYDscqIklKy3rAq21JfXyLipziYzNkTIvYJgKCZ4HkHmZWrUJHyi29glLyTto56S-9A3eKigqsZ_SY0yar6YUBwKR0oCIu0eXht3qkDacvs8L4GdQ17xhmOg=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_umLzWbjX-AjNUM24-DLiLQYr4e75D2dKVtrfwCsEsuIMkul2SrZqCTtgAkXiVMmTwzpuzuIXPwLHUpHL3gRatWPbt-YY-eP9PX7TXwImvK4gQRFQ78VYvu0DT_N_nrdzTTk-yAm1JXKh4NHp8JkiwJnjtf1J_9oQZ2FXKGmkcZUTFIbsTKNOC0XuGwSK-aps6v_I1h9baLNy-7WfMugnYf362qcF51qJTlJ4Nat_e8PPFUYgBMM8bAlw8OSf4XKO8OHOlP9PF0pXbFl0IN-hfW7XQy7PuUzAowaLKAP9UGjqjtJs6eP57DYs1v_nbxrbVP-GS_JYMOVq9De97Z3sGmN06xrqwhtTgYiDYWU4kNSJytiope62jlOFUAw7GqgG279Cx3yNlAkkHg_1lugugjVhPB03aLcE3mACE0QbeN1Qlvrz1cbWGg6ZiC35ivITXPbV2YcJ6utWzu2ent7N2TYY9yzDLjIdq8zCmR4bk4QaRXICiMc3BiMDJfG6xvcvN7mtijusrrM5BJk_8JYJMNFiy51owNFIpM5LNYWbebcUxSZSLthMf6AOt0JIQqxhHdiIsnXcs5er9Dhqs0c7iB8gZAVo9Yg-kUw2wGPEnzd34ytO0I9JCVysvieg0NiYktxBxwH7QD_ujDo6CS6gae9iHHVG8qL243Jgor1in_Z0yCzYlBzJHTLLpq18xLYddiqRFd8Rc7nsw00lXaF4Mai17_3EbVFVLmg7NN-LW9EfMkM9qsQbgWb6tVRdEqwG_kAPx3qSisGSoKg1Il0BMjje0EllMEurz47Sg9A8m312hjJR2i8-8IwbwDdCLJxgUhjrQa91WwJ58KD_ymhzByPrSJ9w2vmM5kkpkUTG_AVIAJvqeHNaTELn1789t3OsLdEMkNn9prJEQ4z4CLHezuikzKE3tWjUfJL7L9C4dmXaZ9eCdfFKH5tQJny3v6bGAm2vpAvQLaMFkc2PJE2ZwvaXaB-oZ2lmLjDWrne6wMtnIg3TdybEE7T0vmRE48AriQJ-OBPCufEvCE2sAx2PbNPwXS5WLtjecjuh3CDDrf6zKVcCQk-bI1f7lCWcSRbG1vb50p86R69Hfg_k9HE8acqEMBMtg0T5J0ksT8rxdiyIKAoqsqcdUW1pJCdkKlwxROwwZ2Pl-9JGo0lrR_IWt1qvUtLXaA5YnECl4d-sQdrKn-9deQOJnHfD8YcQVNBviQ0GHEDFfw2ALUhsCXXWaWSFUYwU91Ml7MPGH7miUn5gkhpL3y6eqypoczCERSovZ-GO2PIEn4WfgzuQmpL0bYuox3pmhq5_jW0t023MOskW6nhy7ScKTVy8hRZPFh3iouFfNlNP9cPFtq4TkPcPscC6PJpXsSpEejmxKuf0-g7L703HX5A0C_wlgKraZmvjP8j5ohT6icHajjwbOhzZRJSWY62ULF5PP-f3J--ViWykb8nYbiauAuPVZGJEZajIkG-fBHsVw2dFfqtWYK1MWUziZUwmsW_JL7P_5WnJX_p0A44_GNxdvEOc3Nvc701yYxQ4zsQH1dO0Lc7OpygaJyD5xy3u2qlcGt3rdzta6UPN4up0MgUDwkjD1kVZZ8tGTsvT1NJ-s=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vEmBrfCm7aXnmqvWnfbfGWxNwBPewpm57Bok-L60r4h0hLk2sQsEv5gEO9fDAEnaco38QB6925cKAH5BMQVOCtlbcjT3r9WZjb8-eXnGcq2hqtwQ8w9-sRjfb92gyPqxQJD4ssIlfs3FzAYTjCKnFZBMh1ChH3dzT4WrhvlnRbnSjN1filDouebhE_3iNId53KreuZXisXK4birApHlC-hs3LYJaPrXwOnDQhITWGC0D_nkGN9Db7Ix8hIvW-jgaDoz2g_ijmwtBPTlljG-CZuCIcH1eGiOKEeQ1-pz1VlqmikPJEWlpx0NpMzhN39uNdknVFu9V11XgRjE9jylVPBzCfCPpOtexB9l_ROl8uuw9jKxKpuFA1R5rLfdz75vDZ6pY2Y_QgecTIxUTf9VC7PTLax4JXwq0eSBrg6eOiQcmRtxBG2Pk-ZZXsiBffd1T55Xwb8JkT-971FNE5kwzvpiGbKQfbAQUM2U598yuoJdgILKtFdjjHKCDbrQnUvYGSAbJzV5FSCfadNTiX7VOg0W4Z6xvyNJQvv8GPxlbZfn_Oc=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

No comments:
Post a Comment