The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vOYJtc0spzS4MNbR_LubfklgOQWWXFi7oGek7mBBuRjjDzazz2MpADzvOA7Yd_MkpGkf6uAFn_vLlgsfNuqrR9hIhGUJzCfWLOo-BTqiR5KUFV8uh-ySdqx3WPTnp5XeNPo-7gkAeau_DOYDAoafkbPVfI5ImVcF6Qlnv9-9WeJIBQuP_-cI_4kN9-SlXbRlNyGz_w2Xz7GTk1JOPB69MQGR4osrIuQzCuUHxhO8kfZXPNeF3EDgiahwN2hK1OrW4Bjd9TqC42CqUKiKlqXTOORBHIMid8uw7G0eXdB37UY3LJvFAMWRqyZP-36Cd2HO3sapa-VdfOtac0CTMnIsr3aWlhtT4wFiEVm0vN43Q777YA9Mlh3Qp7CM8o5wnStWhs2yVUpm_4etxmq9lvXrhhW9W411lz90hv4Q9ukj4Ls_ny-EM1cQSjDlwinoaOrSmFpZzBKBKOId_o7gUeqT9IrfCiHvmqlxhrRau_NbaLW73qrFcYjHMp9h1ZlwbPxRYJj36AnY0MmS083L7tO81iu4Z1jHpAWGJJQegNBdpu1chP6wUFpQA4DFFqLTBv8mLKxdEwcVoKv-640rbF4yHCSAYS8P08EvagRkyzBTvFAzyfYhs8Bqlm2cvv5T91lyut4GKqMna0O1WxGPvFoUUyPsh9oMyA6HUEsDjVyrAv8b57SCgI7o1KnNvvYQNqCqu79PLom5VKmM1rP6-vt4sbFwd7ztZIk8ZujqtGu1ZhotXTU8-RW1Cr3FZuZ1_vibJfsbPhdjd3aAnaGw7BDir1XGrHE54Vh6T8AsENMNMIuF1YnFpu73yn_22Wtoap7cEdcVtHxVGwsmRvGGxqrNLFZkOBjG_53BYm6WL8E82and5_jA33mearrA=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vPQy_RuQbm_dJBzhDkhBzngNQqFeA0btEtvsbmmYXjzs2HdHtCpA6QOn-yFw-MtsJge1gE0lpOg5rXPZNhbGd2Uv2OrfUXzI9NSzoE3K4QkpKNrrVZPywEJfu-PmEXuu83MByQ9p9kKCPOQlePfzlcURNNfeceJCQZnRZL5nJ4sFmhgfIegkdH06QNF6UUssAZMVHNctBL-t4WxS4fbyfitJeeSRfjNuzv__u68elN6JjT6gbn-9o8nHEDwGjVutboH4qxKxsoNSQpaGsNPkCSvy5EBCo0WNZhZFgNbxPjDrGhbzVFUxK__cFAMvVs_wPBKOy7xgMWFu6__dmOD4Lkjd3mgRl6opGwufpBD2D10fEM9ZDYL9lZGZ2iRzWmyM1QqcY7FJLnPaZTamELbllHsqtUcqgJrR7KvDKpTzxJGEJjim-5TM6owsym8xcGieKA9Ptkw9-2xkAV3RqG8IVoDB97Ao3Y-CTz6iJuub21PNWrY5NFss5x7f-yUx6FUVilBmCuoBjpKaz1v__6N8QF_JIIp5VFuMXKZMl5km8Z20wN8s9t2bzghzuwkLXcXjiRUxqRto0MdhK6yjNCVH3hKUiE12BaSlgS3zSE-rJPVaV9KqFBxW71Wr1B9whLlhderETLzjHMdS5bJlJNFrnlWra2-KNnSWKgSzeM5CUYSyojxgDyOb0115ja4G9lVILTlF8ELFHqiuBdohmRub-jNmftUCUtTB7-cA2s-1R8Ivx8IzRFbyPAksPSkrQai--t4O_fI7-2Wrx4JGY2b0G43aFtunhlttMytkYJceHHY0HSADExOKR0kkk0aPRdExLyBdHctwFrQS2tMC_t3F4giJdKQn1f3tmVNJdK_Uy6vK02CtSmnU3WmnYTcbhf869ws1h4W1lJiLLuEjTziEorRjTOwzScQlsw1dUU573uuHENGCukXIVNoMEbRgIoGM1La-ZzuzsD9wWJBe9oogNTN2lXvR75s4jRJFfkAM_Innk65Y5ZPvQ0-Aeh0FG-Uup1lQ22kT1UIUKA5DmyLJqJJOaMpERxKxZqMq5F5BEAGkOFM_uEZHo4Q89AU3Ztp8lbKJ0oYJyyOat9Kl3RlnRGgzQsuqYEA0xILdKvUVYTZQgapNS0rJXvhETQCWXJG0FMth85lkuT6sQn9izmZHQD1r63oZN76QZNQo4rQet1_SiFdEB_I4sVp2iwKOMNFZErtuWCQIzntLGLSYYb46CfFr1SLIZG-4STiTNTzECcdHvNI1bAG9OtE3sY7wOZmat_adDZWEGSvaywyfgMfS-BXxwen4sQqeeEuIti0nKPb0gFmqdH5NdyxhghusxYJCZdLGQzTMSIUsQqeVGlyNdqXjqDlAAEi9mxZGTDlkGwipwKD_g6Kpid9CavJcxd2IdeHqHSYgI2KHBlyd7sLfSC09Sssgp_FuKagr1wTT3y6c0npOoH9_wMMFCByipNx-Yt2uO8C_FArnEgTmKqs57_cALhN8DDRnyKW2VPMgJZ9sh7Mr0L0XzhKzxmaYXCrac3a9Fyi84blnnTYBSgl7q1PGxloTIHOScAnJH7H5mvbm_D2jsCxk4lt2uV9hawEw6sGooUklU=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tiOQB6d66-zrhjA30VzAFBWjroMeqiJ_aVhQ3rN2f25afNq8xCgnyXr1XXNqV8-wqqhj32Wyjec73EWBNI2vAs5R1F9Fy6UWfWrUxKp8FrdJIPmK8Okwn4KlUPJAAVDwBxbkCpIUfQNHTRt4pbBp2OrSG7-xjLwe9_8edjipY0bu09QFb9PddxojlCdARLroqiOENHgdIPiREnbvrGJcnVs4B-MBcAX0kemqqI3jSWsqJ5lR8fGHMT7ksKxAy3W0KAtYnCku2QWukivGy2wHhHmv7jtDqjAlU8MOL2h2NQ-5CULm6Huo5zRy0A4Mpkg-_dBjkuiBGDOKt75Ma5D6WVmWqgtB4itZlKqLGNcBTbW_GXjLLugPtMOhFYhXFzrhvjqS8GaWr8MT2bl0CBO2OrHIlFgUItrETzTsiLw4Cdxs1pVMLyBwFfZBtOSte24DmH76FucFWnswKo1qasGR1cTRbK_aS_v7B-WU6x6I1Bzh-hJzfYZhoaGectVl-zM1LGMUN5TSB3YMh0rrCEiDkswBX-1tmdVeSl85sSIVihckcX=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

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