The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_ukjcrnFnMKgkps-jI1LMsK90PSb3-cdW5CbIvDnw9UHUAF5bcyywhbtXR8YEbs0OZCQ6QYIqkCgw48C4dgiWIflvCE7-nq7UFdwjcpt19oZ4pMwxMHp3z_m5MXtNXRRVbmQ3fIGdM9JOI5kzDVgFjcNcJhgtP6GMvAHnOq3fLFjCvl2af_Qwvws7U0IHGmhsvR9JCXQTdsie77MWH2Wf04yOWejoJg-sAR8Rd5A-5Ouy74jOjrp22SGLPATIdZiq1SfC88FLhpo7575f-xxSDG8ANG70Ov7sPvcQOvS39SWKGY4yVPS1elgn0Cg5vRsavFkXdZzJICvzUnV4XMv_XRmDEylk7iQUmivU58GUQT1cOqksQZNjZ2Du-pxPVhf8k4ZDcH9w5XMLO5VYW_crI4X5p8_r23BNzPz30sjmF4d9axe625GOf3Iz5p6aqRDZFc5IffO6kMTi97wZvxauplDLBBung6ZvE7-XKVq514ZkmXhNqg44SIBvBKC-Z9RlQtxcbafDoM5l1Glc_eJfXi5RFaiEJiw2trWW2xreL9aIX_9jb2D5OO2UVlkIKHK_qRbqzfYJrTcL4guv3xJ29NzgehQK-AWTqOUlhjuM1GvLfXZw_gA6VTcCFrKmblWSocH8UlEmfxkYyzVElDJMHdqE0r8uSdzhWxCIU3eDW8fbc3Rsg3tcP42-fn7jLy_jBz04BCyzInp9FVe1DnjCGIThIr-1nmvuQYKvZsXKqvHUzS76CuabFyr3InsCrOBoLb9JCtQHuncDNlyhUSO2FuvQpVwewmjzs9RQ8QSTXCr1HfkD7ATSuqUSHtN1Z2sBJNlyDfExxXO4YICJmFF6hh5iRpt6qf1ukPlScsY7PblkPRnx5wqomFzw=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sEKgIfPWNSEWZ2VGPfUf4lnIKvDqqfw3WXSsMLjxw_Y66y_31x-oRxVsJT5pGjwlBnlmhGZjnq7TWqo07L4pdsBoj8IdhgaGbs7X0F35LHcN3RXudd0QOgLBCJlmbudUCbbpkGSWLa7MibCyorBkbtTztCT2pFEbZfORjF6BwwPRK48fMpiSTRUSTf24jMH6zbZu8Ijx7IQaEU0tGHfJYJiXzuLT832Ub4ZeYTdVLg4B_Lk6BFweZPqbCOeHkbQ2drPH-PSyWV0ARLXF62ilN0LLw3OMhoOcBC2_2K9qc_qZR5fzzU02B5PUb916VojaKHCr_JEZOy1JpKLcRzLNToZbI4e_sBTt3JOl4HC4VSPHuXCKaJ5ickybjeSTeTqlpRv2sXKd7C969w_LgJz7Vey1clxtfyViv1zzM5HgN7k1lmf2DWEJZxTxzbSqRF-DB3LeTbtOiQNDVEr5W0RrsI7R-W94qw2m9aiZBnNUy8omHYQsw8L5xYM1Q6A-52pBseTAwNChooWc-aueLrT5FaxvsclW1HbGyECZSTmqj6JT2NfSMSauma0EFZDF-Z0pFhBezHWaPJ8lR-jCsOrGNs9A7I0RyRQ4476ot_KWQVaxIYN2xVwTD3hYX2YYTaim9yMHMexg1mbZ2BqWjWUNiWqmXpvBXfMIdWjinuguZIZJMwsyoZW3ATKoRX22dRioApMTlgN4aCwRUSwgBu3GNfLOsxUChZ2DVTG5TbVcuTjCfHvcgKo7LoWCOg61VHVoVDaw_bshqpS6UE22NzV5HZCKaKrU4RXtjqvckAU24IS1ehFZ_OCsCJHq_nJg0_ZipjokxHCjAxueKXwYXv-MxdKDEYK-6UEYeKQMD1PgY1IOUkJa9e_VTy_i5a5XSGnpXtfRlbJzbJEY9QHdj8o8RofSVLSlGqjp0e2xFtjGXJ3uOH6JEJjvabAAa3iHbi6Y02jnWmj2kNDYrZ_xahloxCNjKmvpgs1G1IVTC2XOKpxCsVEuoZQ_8r0gLdk8fO9XGJF2q8hwcrd93W1L9HFGEMJ1I-zLUHE7wjzyZ25B70o0oUC46C1FC8nGVqgHPC8xBq-hoLh9uqjecomNnKfLTsNWvDugRDnzaX5bTvk54YhZ-PVpo6GyIjnEm6oe_CnMyVAHz0ajVtPN2UfomNrfChCvEyqxxOabCH3qO2dfKRhoSfifeFTYIhfNKrwqUxhEhafCUrTHkws3OLw9gWFVJ-lLhhO_LULBmRGEv5fynorlbrIjoWw7W5XDylcILdxoY9hgM0pvbFfwQnOc0n9bJzUsqOXEE6ZAWGI9OfE9ZhODv6pkVGuvHlTSLDttbKhcmuSVgF2fXJZbP-KknD9s74vYazIAwY7EGRVBstk1OSxy7gSODBq_Dp-QwKmrTnQpOFkrFRSge2XZEzA28T8fCZVmKcJpVFe3GpW3_VW2lZ-k2Q8lZaBikhSsJB11HF3WyLFVXnF3LJhQBrlsJGlVkkNHrs3EYrCzWdiX2SSNkmwUGkvwKaldXhf7vORNaJvll3nIsvtgWCML_DScDcjOweAK4KUP6kE8-DhGA8pfHBPjaD7AEHumXRlEcGdeIPlptwCnAoLrU=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_utB3JL7n9KtSrkLmMD9U2qVYhXgjsfOwpAq-IiZy5DMTkcFMrqzrKazzIiQMB8i3zIZQyh9gpc_2KmKSbVA_fmfxDQsKjxYKmoct-OxH_UOR0EZyPrTehDULCcJZfCi_EHbpK6Zti61ygsk6YGAxtRmGHHkGuFHZGIp7oHOn4GORd72yfD1t6aD46FSrU-XycRUVyKGQdU4nUlFI-X3QP9fO3bGkUWBDnLjdkZNJiM4eHtIGEhPwC3rJ2RR37OzxiSMAPUMTiVyzQlDkXMZ_HqnTP1Q77nU97ok1mLvS8ZrOj31m5qQlYZh41kfg4Y0KDuiPGI_ZH1aOgOYlx5zvwJH_5YDsW894rlO6b4jLFFlH_pgKTsoyXrqpELxA4EhmVzmPHeHR1uyJT17T6svA70PoSbZKBn-Zy-yQpEtDPbj9xO9weUQ65T1UIyc_7SJh2WLjMox7YZfHiLdziPfeJg0Rk0R6uWcn_YA7-Y_WzpscUa8zhtuka23xJv3GddvMhVoNGYNqxhOT---O69NPimtgS64I9iJ4Ke2SdWenkSU8-Y=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

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