The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tUKc_ErKZusFPbRSmRg0PD0Db7SefNvhC7e5GaoKzI56_hip_5hxf5orK-KwZwbKoK42OlPWXixFr7jv_0YZcCoG8KkK3WCjgz66gH3YMYKjOTe-JRpeUN6Yqg5dHjT-7xuAy7nNBOEDPoFamndbIq_au5pcSyRv6mUElqIlXjWdRfDe9fzKfBxkwlRV2iAdEy9QHiiYnp8bT9ehB-w3JJuzFBWRzmsSTEUchMxSG1XBRaCG1WorYhyNPUIs5ivE1URSNuKs8wbpYJPrxFAf3YW03Q7mWuVfzOz2raPQnksJQR-Btn8E-7XU3tsIaLk4k1XhXf_sf_QOski87oQC3oQj7v89K53_WBameL4NPD9OSlsQpcyIflwojZdY86FKE165LByo11mUkv1j3BQvhaE9IF97vcd2NqExCvegUjLOs3Z6wIT1Xp4QHtAS_FYZW9LT0fL7jN53auzcbjD7XcQ1BqKLauIxzRGFOAcLxr3v6CgAlccIaV_JCtrLk_KVoPNXFExHA4lWRIQWZo1OpPYcoPVEl-yQhl8XT3q5COLLensOC2mvKsT_IzoqqQQdlsFjr2m6DJ7t-U9MDeC3RmDhtaBUptD9vvwuFNBayDG249Ppl4Pu8EgGGVEN-jGm5PQ-WRTTfhvxSSY8gQBQT5tDB2KnHraEZEh6thA3RE0wSXl6KPgK_99DrZh523DImNxnnBAu10geTZRP-RYnVdN_3xYZHEu8n_GdS9iJIE4mk6d8RXAhfNhhDuGVIE2nDjDRMbLP3_ExndVrKKW8VCLL9ie53r_e6UR1QLd2EvhkZ6b0SVuHToob9OYK46GEZD2GOgzTO3LOBsyay0NOOFkgPX-xkegZgcYPltFvOirmDOYwJeZKt-fw=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vzK00kxjWHpIqM1sQm9OH8PSzhTbQ2OHSWBJFs8858gkI3snk6rwWH77VZnsiD8bm3uL_uYmiUlQCKeG3mpnr5Kn5M3m3eSRrAm2DD3wruaOlza8UvnmP4E5bEwD-YZyU8nYF8BsYmV_3wZOE3jHqIXci6J697gQUq8YC1c8tixEC7pig2EuhxReg8_oxsaIBNxp_EY1BjZhmlAbkoOeeki8uOPvPNlMQi7CJPMeWhMe1n8ejc7bA_qEPJiaXZJeyb1_wElZ0no6wbpHwWjCPRaMi6kokHKUBjUxIl0zBMDVdOvwDBmxROBvmwgySrtt-XnauE1wgQdoXUILd7qiCv8IoGyMqsuciHmryxIeYMxgL1gKDfCUA7-WEuitLKk9Sysy-Kap-EHC76FcD-Pj6Y3RBFxzHjsM0GsV9NZnXmRbu9qTUlKcDl_a4F2GUh6hgGJOH1eGMYX4NSwZQ2H9cx_g-Yr8PGWWu9euGfd-sVk_GP_OaLrzTdMohlW6ZMbUXqvIkEpg4itqcXsgaKHp4qNUQroknqbwhb7B19OOylu10mzwwj87nv0PEpKNEPQGpASjEEPN1zwgMC8tF82Dxvc2HpxPorXQuNal7Fd_FTt--MoahXiy9wH_vNVUKwFKBkznMTpS1A5bqFIhsLQaNQ1Q9CB4TOrah8yKalwknm425SCTda2UzgjeBWFMJMMyq0dhdikA_u752OT2ARGa6JmbhrGsa5X0kb2IAcSLwebSXIc9LoibNuWHRLYY3_hrKsWGDMjGZsn30Wb_vuJW_VcC2V4MemFFkGTtSaBKzKyISfYwX1UyTRfp5Y68-7BzfUyCEqQfT-SlCxnDc69ZzoZ6n-X3ABotWjA67cNdXKDl1h2Js61I9KneE-uW9L4jF7ITGtzMeua7ADU3iKU6LFfecsrnosF3v-63UkjoiaUkektyG50al-wit-VTbFgMpqWvEkzBZBK6Ld4bQQ5YF71gpahMI66TT0ZVqd4bwOJZOdu_vso6AIGvhKTkLujwIG6slSWAEi3lvt9lNBMWs6vh9ZOuwnXUHTna9IZ17Q_nIOTBTegCZk1nwH7zvIesowmhv1H8G2wHOFanAf5pPg0sUOFiKOjfUhGQUclSLqFWQ2TX0ELw2gXnn9VgXkvm1SWTmO4q23CVkJEWEg9glle2d5FzB0KeFlNPTkBiopr2mqIjpRs4bteino8v3oZlrojh7aDndHfqFvC8MXe40WUr1oVMb9LN1YiVpba4ltG9gpv-AVKGMQv0sO42LvN8mU-QARhxwjAkBDbyvdLwq0M-wHR5qbt8OeNDDLtk-1MpUrL9_QvOEzQ9KloSa8emzF-oAPV1AhvYIcbCPiiV5mbHn-LHjaCD3H5gqoYcWIwT5auHL58mymmSyqdyHljipZuv3VkwTorhJE30GzCqdtHBxZ18kyvr4nwa8A82GpcNCV0Chla8o8ztxgajN9_Bjb29HZ2K-ven4d9e7MH3yQaTHmWu0tUy2IawB5HJDtu-Sn_6yyeDJizNpPeXgpx_wivLNRIvJZuPsp3plDEUxn10vaesIRe0ixhwWWwHDui-Exb5e9_fyVZzMKEGg0qz4URBP-frA=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tARfwHUXIhH5gsuRtCwnHszWTXga0F8l_2jNy2iR2vtUMdMikUJ9O0Kn10EVvRcEP9Q1DdwGtikOgV26EAu-yY1Cj45PcJNP7YbqhHt8ERVZhYlufyNlZ6JQRaf96bXkpi6OGrFLfPyeWQhtECmhsULdUimmaECIeAvwfVO8Hxjq9IGYPF8eH6fQjc00fXM8DE1UPcRlhSSKz8SwsxAj8dL54xwr6EDACfG-F9bfIkj7FRNDcf9QiEImjIcHcJtr5bxvcR6R20WGdt44azbQYCXPPrgGuuRQBivFRkUHXvprb5qTYSI0K5WA1_QhQMUR8rMtTLmJSpaGysArykf0_F3nXrxujo1nrjgll0vKch_-ir-Ly7D1_N4nXY-IKrbfUBHKc_P8p7W2WwLZ12jwAOj3qCxdqMlNI9rLglkPl8PYmV6g5sAQY6P8aYvuWgsNIy1kETcHYaxTCLzaB-MWqrOf3elVRuJEI5Q_xjHM_1J2efyKAMvQsk4wS1RO2Qysq4YZgyzOanEnQpX1yCDOvvGQX1rfu6grUdOaRahhUIF_1l=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

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