The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v8dkvV1pOO5pUg180JHBxQVSdFCMefp6I2eb93jrmH0RawAu81hdHWPBMBcYUssQpJ0gdnQzfeIDerEj6jgU4BbW9WX7faaNEyEF0wPo4tIB43pDw84PvpAgl10cC-NgIG76HumzX8Q_qpfHkETabTUCQMt9GLBemmvvW1qmXchRSzAjGENnjX1vm1hEZtkFubQgzrKKzJGX3q5q6pbO3WLNDexdAYqE_meuTTMobAexmzV3LSGBg35Octcq7TNFLshBix8j95pYtPlsrMkMOBxCBoYkuo97_xpu9hxmnp0YzXx0LHlQJ-hqu4HmVuKp4ObIDzc08yiFoxJP014-SkYX8L9wk7gBpYkWeuIFhuR0iFwJP30MfxqeM-B4VY_b8wba2yJE5yEYJfGBy4K3hL_LVFhQTEg58juyiNN9FfPaVn_7aQy99RAX4KLRvla_Q75rs0hGG9JNE1NH-agjoACzX5XIQpSH9-flUGYt6SczvJ9nX9P0vS-XKO0Br9xpwKKSF3Z5oZzTOGz5wzEolWLT7lUdMtDTlL0viau0haIsdNhD_d3T3Yt58RkxuARQSsV0ZiOpDg9SCIwt_2AZBcHA2GYdisZzg4iQWNpuVgpxxIqgWiJS6lUGnyA-fi7LLKyJhNIEPlNw5mQbkcdL92CZy1wT7G0Kpl_2a9rLtfFR1aGsZ752IyYt7Dacfk-dNta8qlaV9Zr5v8rjvxaoCtRgqE3XbcKlTjHiM5fIMh2DYcVOFmaca8GXx52v4u7C8SbEMjrSQ4Ha2rHWOngpIkRcjMMjxfngzLnfm7_qCZZODhiNvOwxgKTSZjKp8wteXEevOjtXK5Wc27KiTp0Y2Y-foeFMTlKlbuMeVkrx5XiAqVr3G66d5ROQ=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uYavRkndCZhFDXB_YhIT3ljEsDqs2G5gQ6K9OAzD8mZj54K6HWnzJolBUe6uE5Z2HxoraBY2h6AyW568eBF7-WljF8bMtQCj8F-AgYulc9Doe7qUsjudbfkZ171ad8OqYxxGVcvJrESiJ_h0y14Zi0YJAHVw9HCff4LnARveqNJYkBNbFM-5L2WrJ7ehHfpvcc8VdLxf_q4rk0ysCxNgMkt9TryuQTOcxV04xw6Iu7oaWgesqxeKQNu5ZICygiZbtH3_2lqT7oDF-MsYn8LnCdCt8c8XTp20l8p7zC3lU8Pc-TTqh2brUxjZ3bwcaDOvyXv5kkyxsfKY9pINqOwH6zKrHdToTP2gxzOUixK10rDtfrmSB5EkdNZH8KUsg2SVf1Yh5edRo1YCJBnhArqCKRJe_GafEkZmtXZpQIAy_QHQpR4gzgEGFknqDUd3Dy_aJYS1fJuo3rFuB5kNseIttjbKm0E_dnsqpLEJE_hB4xBcf2j36R9t38ucw7eSQG9P1dvRqi8IF0sbLr96D5OvEi1N7lkglKWvy5DeslncGSi6dqOe3IY-ymJ4VFrM_7MO0qL2J1L2NgEG1AzgCgGsKQ4wHGKnS6II1BAr4ealktWmkYpU-y4OVw3LbeuFFKoFLmdPU7WkwPyfhUlx4AP-GIHsTz41n67IJOBSaj-izs4SFeKVFA0gh31WW_CEufXksJa0O_MVptEl-Loa_BV92ocrkvjPfr0bmHrzPb1ByvnPkxe2UX1Rx1-BCPqYPaSboHWFdqa8KIGgjniVQKKjHMsrkkv2NIQgrZe7KsKzRLEZ1UGqhpQhuyncBrKQ9U6vYobQ4HFwMxqPM_8xLBL90pOYmjVM11o_LEWwOjOIOFRLyzEZRaYas_q9qCxwBr-yAav6EiiVbHNTKv7MSmFmlB9Z_H639O7Fi8aoW0Ja3hDXhIEQTZGpDr_9enJ2fi4ubTE6nUGjDpZwb0jIiNMU3tyGpxeZwPoeAfmT7pzTbVYt2Q0avPsEwoy-kdeHPwGJSKsldlPODH5CYWhDbjjYP_m_U84U7ROThWcblZdCIPXQCYPNi97s061SQQ3yJciBqdi09G0nSoeMRa927FuLkqzdBcaH0MuYGPMT-mGReukyJ_n3AxJtHNBJE5mloW8wLF39PMe5owA336ooo3C84bTTFEV3-A6Zdu9PXqwWb3tm6cSRurT9iS4Z9RRyIWqyY465SO8Qofs1t7oCL09QYiqH03Et5dE8_XJPgV0YFu7YbRamt-p1O5Zl5kNWyPpcMsPABl9njyFCxxz_jNvAuSto5BjJgcspZr9rhTAdYBTgDVuAi7FFQo0uTa6fucDneN6CBYriZF2QE4dDtADJ57sFPDaq9yMGUgLB2nvB__2HWtfbmQn-ip-Bwd7pFQGQbMRtzq07AmeBeZSlHN6XgEiQZvlTs2hU5oJenpxUdXpFpG_Ny0DA0YST7NrWgByssGs-ZYvP9MQlznPurYEkYhTxNfadzkglYwBOPtI-EITxd3rhrTEFqeMEUvMnPyv9qi1dXhqWa3RwuTY3bvJryeRbNVoSgP-OsiP9nxLPAGPVZjmBBVioxTwuTcwUF0mtrwmcs1_1I=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_spTtJZyVbEVFiOCJ83qwOeotVohuHohg47Uymi1TM1f_1JlBCe5ekfOo8rN1GijMCjrtkGWFBNKDq6zbAOlf7OB9WEG7Xh-HazzpqjsIS8aRBrvhn3CUvAb0gY88NSDxYseH1fjBxLtJl12XrW9VuxY54B7ChKenJPRSgefGTWXkREgR7Uo8yGgRN9egKQSfO9-ZIUkdzLBoQyta0bXohZUi2FRPAM7lGkvCe7FODMhTWEB-An2TEF7g9MwLVsUCucFc8gqyK5iFOlnIZRDxN-OMrmJTxtJXxDbELkBDtPm10Spud_hszXo-f-KNYCpa8uq5aC5G4v-BUhqMVRS8r83EC9RLgn8VIVHE5MzLymc7c5FxrenN1Pt2RQtTae66G3GQigy4kWSUHxAYucPoIFei798ac9PwhNdzcx9yndBiiTv8kJOkf5vTiZOHRhJSJNV8xfcZWqsI2hRrikUdzGjzUGNWpUwwR43bls8vx3AqhYa6QDjiplTvNXOARyuBMmXLoEfvHtNNyLNq1HK8ab_bLUYIv85btVfYxtOSc-AcgE=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

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