The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v5JXM0Cks-6HMaQIU0fB35elD5bvptvGFLliLYzIJ5AdgnYdLjSTP1ochCQiC6EaetqwpKFSsUngK_-TyCGf9U9dpZsLGurisKliPVAu1yjpWXf5KpITJgLHuQQkjwHutUJpAoE_7aq4DdRSGtnc_LNTj8cMuAkR3cjpDdrUfY_MU8Pu7DE48z0yS3XSPLddCWyI1p_yoseBkiDLTAxmV56BwN2SEmxS8jSamQi1qN9TQJUb7pVKt9g2dPt5amqi7IGXd17FwHJ7kqSPkr2kT6wQqVwWjKhpOieg7sEKJNg9lqPlF2FZQQpCmkKm_to12K06PvVnqXU2NwN0UuTGi2ik5ozIEHCAOoZm1k_-jN1JkShF6UZkbTLBGWYDrvstiaFFU_F6joux7NUz_latTNQ-RfElbK_Z4j9Y5Xj4Z6fXEQ6mDm7tBKn_nKHKAra8iM50vH3nHNotS6szrZmGZoYR35NUh4Y-n_v5Z2Sy6MiBR5ttPJLDv314jcNfIPukoDrgV5hWDfQPCstVp_tTewEdWfpaLW4uuGRX9aj5E75MLgVc2IetBsPlreMaQCbv19H7SgDOd8vaLxRwhSuIWX4f6QYvFQLHSwSakEtalzkEbBY062Ii0AlmqAt9NtE0IJ4DZjb0n-BDCrnHZ7kv_bRKDU-tOzVMOT1plGX8_nSntMvPsy5fZx16zM6bVLckG9yTE79WOODy1pIjGaDlxqNYBOo7FrP3FwMkOgR7SBlYtgsAkXhC9I26QOpb3AR13F81CoiykTns76eIxw46npRI2CYj_ptan1t075OQ1vrSwsYyjKtffNEDWU8ixP8-d6HfEPgiVETNObCMzsdIhOzg6HOCLjSprocekoZVQNROnAIlHaH2lXEw=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u7hEDFA7QOT28z8C3bjuJm8wziKNiZ-mAnVVeFjeFE2TXjqb3pSx_j2_c4L4dG7fSTz7jM05SSdUtvnE6ix3-ezQbb6O9flR947JLCVqx3bfRoLLJddnsRp1gXN8YZAeUuDqiKZ8_CZ9Dhx5Evzfayd6jnNHY5c5u6M0JS4PRQE-5mrRypxjGFU5fA-h9gIY_OXhVGsvRimieibFdzZvW6bCMJIHicTji0o125oqNOpSjL1wXT8wYM8FSRMkGsDnC8liRtWYBAklPLwE0zArGLAMFI_QrdZz2lef6zwBHHT-RArpXGx5pS8s7djiCJQ11fYuyQplRea1wEtOR8z87_FXdgBX5V3OnGbBDvwaJF_9rJzFmrLX1b_mFyHeFoQGgb-kOLN-sCRu_IaktBPY7b0MNKiRNJUVHbZA-Eq-78qVlrhYD2c4ETRV7ccVTq1qosLa_TkCK65P7QauFcD1_9j-19Z3VRzgYmDKl5CmcqD0v82n79LacfezlY_h1UCJyPfgNLc0UrQrfzBDmmEbEvosm9J0DBkIOeMRvyftuEYEh1L5CMOc_QGsRP0owXVqbI_uq54NqHGLGXs2dZrMAa1fGon3HTSo3stVAU0KYtnMuKlns0XssrSmHVjz3aOImxvfSmc4JT9tR1loCELGQnOj5n0K54VqDZu92NlD-4uZT7yJ_OIoyVLidlkyK1FQ-nTeAjs_obpnjgzSvAJUKshRfXAMUjQddqY3KKdr2MRVYykk4Kq5RhVh9Ova9d38MNHuS7aKC0_S1YorKEVhWE0S4OgGomY1J2R9T0UkMH7wEHCMcV2OPHa-hn8dqHfEEOmOrc1ZWkL-gMOZeWxZD2CfgqdGFJwCyKj4nAEyQrLdpbnJyyW0zGPdmfZJfjDVNqHFSDtqOzGGh4RXUpbCduh34POXXGPOZ0QUKVsUSjaad9CRzTYqbKLoCItDJAd6o7zPr7zdtOVfDVDLexfJQA1waNPzZAnPkCJSbR_fdEjkuS0HZdg7m-F69DvzEbS_Fx8KGr-YebKDCWA2_m1UawigZt4o3HED20HJz0U5tgxUciSlCDrEDnZU_wVsznwwiQ_TG8UZ35p30D3MNgfrW4380EfMmHA_jOk5eWk7emZaV1G8qXEJSxXwgIynxnqtPRKWVhnhptOI02KPqkDczwzNB0AGTxYQQJqGntWm1Cs1wO2Qgbzz1tlPBSIT0voXp0G8-1Qlbu2YL3uvZ3AQfSNu0giy95hYe8Hk0IvqHVybWF_645UUYx-IsF-W3duV1M_cA_YF-mrAYvbIXqGcjyZrQ6MTAT98By5lV3vC3wipwnYCJD4Ri2Mpe2gevSiK0IZIBuh1zWXa4qMUEtoyTA_aOyVM_qK9etW9vEKEh9-_zU8674X2uJBdAeUZsUYA_USF1bLlLkP6lSopGcDGL1fB6Qc5bsMjm_E6nNVZ6RllIM7QKTBAHBTOwwqtuwDTvD1nUobI6gBS6nMZbBuCfnRgn5ddY4YaKDvHW0yXc-qcZQInpLm3PWbYR7MOize8lCx5ipIf7cawokhlIQT4IjrmYJZ5vpwSBjaZuTnAtTjgBZbtDnMg12gPwdSHDPgsJm1wMPEYw=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sSyItYccNneGbYOPzc3WMPTyYpMqoU8t65TTWXmM9OU8vzexGeExzfXwnfm82hcAf5Z3N0O7V5_VCj0f7D83oZLxViwQuq5HbZklbIPXeG8e_QuKYcYfa-rTn5KVFrdy8un4eH9Pz9UKFof85od5TjfH8ElEVdgQppoWXLcoPegoHRBQaS_SKOxY8oZrWW8nY8-mavaO_URO1Ch5_HNPz6EH0E_Rm7EEq_vR7fWTsJFIaqH4MTe--STnIRybI7_j40zJMd1sgxZ-wjI741NG8v93Ii-cYv1tMzI7M5ocjhK8WmGbKAyJvUh1UR7bSzGcdP3hzizRV9nVizIVaI2b0MRkS3UDUKDw0wlSf9Y7H_2Mn69Hl3OSj16MEJ2BseCF8ihl0h77PBf7eVYIvy4HuLYK5HQy7TUsLhgfUpIi_YQASArLLSP-nlv7MUgkQg0d5QI2nr-EVetCphZTLwaHu9vj2KcBAeGotmeAFbT_3saON5jVXpNFRXgDV4vKyI9DqaT-Om1V8hNTscH2wtFU5N-hbMsJ7j7mW87j_p2jr1dVBO=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

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