The angle measure between vectors remains unchanged if the systems of equations which define them are translated, scaled or rotated. Might as well check.
In the image below, N is no longer aligned with the z-axis. The surface has been rotated by an arbitrary, positive angle, φ (phi).
Phi, fie, fo fum.
Ummmmmmmmm....
Oh. Right. The math.
We have, again in two parts which may be done in any order:

The dot products:

And so, as before:
![sin θ1 = √(1 − (I•N)^2), sin θ2 = (η1/η2)√(1−(I•N)^2), cos θ2 = √(1 − (η1/η2)^2 (1 − [I•N]^2))](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sIYq831rqioALiepKO1HDht6t8ajaGiPb1iRwMWqsadIUpz_7Rq24SJQPZMykwGOXTTFW-iF8QR1d_ReZJXFKss6JI4ILVCTJqQ-SkwWOCP7KxH0_9QHzLDEglbVbXqkaE-vjKjJcYeshoQbEfo0P5Yw35rqiS7JD7XZmpjT7AjnubrlwfUrewx9ZU-utCbp6RATbk8o1NEBDKZ0nhz3KMf_gP2zJERMNhYUCXn8O8rkuIDbPqRGHuIqPlZFhtu-BfzTkeaHzdpH5Y-U2BGL_dHnFaalhLKNobz81DLk-ZzeT5Ka3vfOyHtCr_VzEAdKR5TBwu7VnS7_KvBHHR7XklUlfb_sGc6uGolyAKR4lgqIlnSM9Y3tpUsDizB_AhWI01VYLThiCQatshBZhg0ZYPJEqW71Bse-JPFh3dpYUf0D2gbwNLr7uoKKYtsB8MB23Ec2f0-4wKXJvGZc5zR48B_s6XeQIqYA0zBE3TNt0oJNeUxlcQVBU9vG1G13qkEU_URmTYEHVaMcE46riQgGf3xvTXXW86O6ujlBaQrFCJ_qmCWk123JVxycoioBVTzxjaid6gTa_q9A4x_fQ76SCLYCU6DzeRyWP3GvgSXI8hkpBpYGQSYqIoLQDvofkw9Qi7GUGoVo-14_YSBx0rPmBTlu3Yi9Rv8ZDJ8dH3iPBPWQdANY8nAKJacyAJ6t2KFSNxPqql-KBBRaqi1ymzXVcDAKw238CDVM7XeeRYpiRctwN5Tc_VLpzKii7dGp2Ibhg5LTUy--Thmg422EJ7MgX9PiqgetBEy0O-W044GlT4N2Cw7hbQ4HhAxLytE4OgrvKG9t0LExEIOcAIkGw5t5V4lp1PAY5IfzC2TLuY2r6GPwXOnbYTd08TJA=s0-d)
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
I. Calculate T for any η1, η2, N and I
The dot products:
And so, as before:
The sign of the square root is taken positive, as defined in the last section. I makes a positive angle with N less than 90° (π/2 radians).
II. Give T as the sum of two vectors
αI + βN = T, α, β constant:

Using Cramer's Rule:

Solve for alpha:

Solve for beta:
![β = (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) )](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_um9OdHoVwPiTKCfv4CDdTim2ewAIyKkGlG-cYWYS2HhCBlIPY0Je9l_5W_qtJ7P2GzEn9Rwuys6H5gnkOa9s9YNnhuEBu_R11tPjd1lXM_ZyBwBZN1Nww_Tibn7MvI5wOuiRZQugayUtMRTAyN4AIERLWl2ko2AadSoiB7hWJG24YTc9D_BPyP5LZoLywlZpSloz2_uVZRPqRvMUxWYrFCD1fPWlKHRodXGgyi33Yl7arQEEku4octh6PPQRMcVF0A36M0xtxVlA5G_hJ8RjwZXWH19NwEWrbVUiTfvC0gaRGgqnY0aw9Ix_Bn0yYhIpMJEVVrM_ns8Tg3mhBQg_lggeJHbfDQIkBcqCnmjXj9uzR5VtuwUiOuzXorI9St8Bok_dlJZfKtnMUgGDJtvohxZA4_qkmGItJvU3jpxPxrYA_KfQ-g0v4ESdlNKKwQd2o-ak9xqRlZaO2a1Gb-1W9YFFmn6zXO36pnwSGEyHXPkb5Oko33Q2qgFYK8Q-befUOUKW6smpP7Z5hWhNuwdo2AtQACCPs1QHuG3WWEt85FWmjj_iiEBJsvBlC7xKrg6NX32gQzh7_JOlYf38o1EaA-3NwudGbwzezXtel50igcDREQGwnEWYCXxqEBMI4RJILImNyHH6Vfg6B_JJVhpG7BkPrVTxpkv-D4tyX4uqcglM6cjwWQAkAJCBgIbbH6M_nol7dm_Ysdvgw8-OD_6lg9zd79GrjPpu2T4_B5Lv2Et5h-gmxboU9V_ReoprU-VuzErtzoIi9i1ZDMQSbWS3j4HnNA3YPGwWmL1FTkGhahKAIxxvaYnikUbsrF4-3QF-UN0DniCVY9raNscqYw2mslgmideVZd8t1kBfoazzeo63DBRhMSDrUss_UW0Y4lJmDLPCRxo0G1tGErlA1eHhfdzOstbS54KSxoVdxzh_2Y2EuhR40MvYrfEK99dF-CX4iq5uWJh9M775tpoBTEugLhv-Bq3wyPeaVd54-7h8DIdArJoP_4CgK3NsBhIZUk07N19wBKWJUsepwtscR0b2GVnnLH85NSOJgZc-NeGtuVqJh3yEUh_Y48pS9LAjk6R7JC1GDNWv3srJvALUNDnJSkJ6_R25KJ_xM84N2XXCBUcxHovpH2UXu_MYKaFuuj9DR3n2ko9aMt7ouQVYZsRPCYItlyXMFyjYNhTdhvkAL1ivt753hwu-27AwBsDz8A1yYBlqhV0NVwYa0HeJU3vClfE2XRsjPRgGW3PagSPN58V4W0V8D3DmvcOU5efBnh448OiUiCYgE5_y16SZFjcKXj-4k87S6holy7koR0-N8Oj4pBNprWPN9a0g5iA5aoLdzZ_AlxR2hAnAYovDqtzXDQDZC5zQf8hRmlLAQ7zL9GcGYlqEoHFRVsCBG6hpGGdnpRnBihGRV3mpTxp1oTdhQ5rUHgKBUtSkQMUwLkkO24RwTGqrZZEUyw9M1yaVVtARHeegsZ1akFF8auDEyWhWtFsh-MwjgszuILTljB5criITPvOBtD5WntvpJudhauURShb8FQCXXEGSYdhq-AvZU8AWQbLUatD8qG_5vu8KqW0c9dWwrg-mt_duE1Z3p_hEmbexrxk4U=s0-d)
Radness. And at last:
![T = αI + βN = −(η1/η2)I + ( (η1/η2)[I•N] − √(1 − (η1/η2)^2(1 − [I•N]^2) ) ) N](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_ut9ns-_ZkuTX9HwJlWvYrmpU3DdE_OlByoIvHXf_tZUWAdiu-1iUUUZu7k7Q1v9_3FDXKGuDcR51sJQUYj4STdC1xP_neHtYp7AbC_rvpGpA32ERmnhM2uOKxXHMPw79QnzaXkzTpxy8x5Z3GIMG8di02Fg2tnKqDA_TV72AHxVJ8xEBM8JKtCfX47LtQCjE7EOd6y7Hvmt8Ub6BFJcC_HmgGpBoY6HQkJfHcsUDFZ37v6gXP-chTsHDXt--HPG6DTlCn6t2gsxmVWIKseGvcNT_UC52pO4oUjxvCKbrfL-RuqLqra4hVZia9JHlDIpLrIrXswYSr1iQYTBTDEFoaWHiFulqvm18RWKS_rzXaJlB6rybEdGwR2SuhMZr149apAEbhz99h9t2-Ohg4DZO38PoazRR_jAtmJfBKEmSgx-x_agotPY8ReP1A0PA9oe5u2UKvwBJsa8F82hOgS29DthObN0JToIKE8LdMeCKr8YVy5_MAzMHuUkyrrIeAxO866DMlRvBftHLKgiy-kqM1biCGdE5nuZ_jopZVsErxwUKRQ=s0-d)
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
Using Cramer's Rule:
Solve for alpha:
Solve for beta:
Radness. And at last:
THE RESULT
...being the same equation as Parts I and II. So don't do it this way, because it's harder.
(It's over now.)
{CodeCogs you are the warp and weft of my Latex heart}
{<−− Part III} {Part V upcoming}

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